Question
In covering a certain distance, the speed of A and B are in the ratio of 3 : 4. A takes 30 minutes more than B to reach the destination. The time taken by A to reach the destination is :
Answer: Option B
Answer: (b)Let the distance of destination be D kmLet the speed of A = 3x km/hrthen speed of B = 4x km/hrAccording to question,$D/{3x} - D/{4x}$ = 30 minutes = $1/2$ hr= $D/{12x} = 1/2$$D/{3x} = 4/2$ = 2 hoursHence, time taken by A to reach destination = 2hrs. Using Rule 9,Speed(s) ∝ $1/{time (t)}$ ⇒ s ∝ $1/t$$s_1t_1 = s_2t_2$(Provided distance is constant)
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Answer: (b)Let the distance of destination be D kmLet the speed of A = 3x km/hrthen speed of B = 4x km/hrAccording to question,$D/{3x} - D/{4x}$ = 30 minutes = $1/2$ hr= $D/{12x} = 1/2$$D/{3x} = 4/2$ = 2 hoursHence, time taken by A to reach destination = 2hrs. Using Rule 9,Speed(s) ∝ $1/{time (t)}$ ⇒ s ∝ $1/t$$s_1t_1 = s_2t_2$(Provided distance is constant)
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