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If x is real, $$x + \frac{1}{x} \ne 0$$   and $${x^3}{\text{ + }}\frac{1}{{{x^3}}} = 0{\text{,}}$$   then the value of $${\left( {x + \frac{1}{x}} \right)^4}\,{\text{is?}}$$
Options:
A .  4
B .  9
C .  16
D .  25
Answer: Option B

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