If x is real, $$x + \frac{1}{x} \ne 0$$   and $${x^3}{\text{ + }}\frac{1}{{{x^3}}} = 0{\text{,}}$$   then the value of $${\left( {x + \frac{1}{x}} \right)^4}\,{\text{is?}}$$
Options:
A. 4
B. 9
C. 16
D. 25

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Answer: Option B

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