If x is real, $$x + \frac{1}{x} \ne 0$$ and $${x^3}{\text{ + }}\frac{1}{{{x^3}}} = 0{\text{,}}$$ then the value of $${\left( {x + \frac{1}{x}} \right)^4}\,{\text{is?}}$$
Options:
| A. | 4 |
| B. | 9 |
| C. | 16 |
| D. | 25 |
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