Question
If the radius of the base of a right circular cylinder is halved ,keeping he height same what is he ratio of the volume of the reduced cylinder to that of the original one ?
Answer: Option B
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Let original radius = R, Then , new radius = `R/2`
(Volume of reduced cylinder)/( Volume of original cylinder) = ` (pi xx (R/2)^2 xx h)/(pi xx R^2 xx h) = 1/4` = 1 : 4.
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