Question
If the measured value of the radius is 1.5% larger , the percentage error ( correct to one decimal place ) made in calculating the volume of a sphere is :
Answer: Option C
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Le the correct radius be 100 cm. Then , measured radius = 101.5 cm.
`:.` Error in volume = `4/3 pi [ ( 101.5)^3 - (100)^3] cm^3`
= ` 4/3 pi (1045678.375 - 1000000) cm^3`
= ` (4/3 xx pi xx 45678.375) cm^3`
`:.` Error % = `((4/3 pi (45678.375))/(4/3 pi (100 xx 100 xx 100)) xx 100)`% = 4.56% = 4.6 % ( app)
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