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Question

If the height of a right circular cone is increased by 200 % and the radius of the base is reduced by 50% , then the volume  of the cone :


Options:
A .  remains unaltered
B .  decreases by 25%
C .  increases by 25%
D .  increases by 50%
Answer: Option B

Let the original radius and height of the cone be r and h respectively .

Then , original volume = `1/3 pi r^2 h`

New radius = ``r/2` and  new height = 3 h

New volume = `1/3 xx pi xx (r/2)^2 xx 3h =  3/4 xx 1/3 pi r^2 h`

`:.`     Decrease % = ` ((1/4 xx 1/3 pi r^2 h)/(1/3  pi r^2 h) xx 100)`% = 25%

Decrease % = 25%.



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