If concentration of OH−ions in the reaction Fe(OH)3(s) ⇋

Question

If concentration of

O H^{-}

ions in the reaction

F e (O H)_{3} (s) ⇋ F e^{3 +} + (a q) + 3 O H^{-} (a q)

is decreased by

1 / 4

times, then equilibrium concentration of

F e^{3 +}

will increase by

Options:

A . 8 times

B . 16 times

C . 64 times

D . 4 times.

Answer: Option C
:
C

K = [F e^{3 +}] [O H^{-}]^{3}

If concentration of

O H^{-}

ion is decreased to

\frac{1}{4}

th to keep

K

constant
Concentration of

F e^{3 +}

ions has to be increased by

64

times.

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