If →a=(3,−2,1), →b=(−1,1,1) then the unit

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I f \to a = (3, - 2, 1), \to b = (- 1, 1, 1)

then the unit vector parallel to the vector

\to a + \to b

is

Options:

A . (23,−13,23)

B . (25,−15,25)

C . (2√3,−1√3,2√3)

D . (−2√3,1√3,−2√3)

Answer: Option A
:
A

\to a + \to b = (3, - 2, 1) + (- 1, 1, 1) = (2, - 1, 2)

\Rightarrow ∣ ∣ ∣ \to a + \to b ∣ ∣ ∣ = \sqrt{4 + 1 + 4} = \sqrt{9} = 3

Unit vector parallel to

\to a + \to b

is

\pm \frac{a + b}{∣ ∣ ∣ \to a + \to b ∣ ∣ ∣} = \pm \frac{(2, - 1, 2)}{3} = (\frac{2}{3}, - \frac{1}{3}, \frac{2}{3})

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