Question
If xϵR, the solution set of the equation
4−x+0.5−7.2−x−4<0 is equal to
4−x+0.5−7.2−x−4<0 is equal to
Answer: Option B
:
B
Put 2−x=t and 40.5=412=2
∴2t2−7t−4<0⇒(t−4)(2t+1)<0
−12<t<4⇒0<2−x<22
or (12)∞<(12)x<(12)−2
Since 12<1∴−2<x<∞
∴xϵ(−2,∞)⇒(b)
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:
B
Put 2−x=t and 40.5=412=2
∴2t2−7t−4<0⇒(t−4)(2t+1)<0
−12<t<4⇒0<2−x<22
or (12)∞<(12)x<(12)−2
Since 12<1∴−2<x<∞
∴xϵ(−2,∞)⇒(b)
Was this answer helpful ?
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