If three objects of same mass are dropped from different heights h1,

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If three objects of same mass are dropped from different heights $h_{1}$ , $h_{2}$ & $h_{3}$ such that $h_{1}$ > $h_{2}$ < $h_{3}$ , then which of the following is true about their corresponding potential energy ( $P E_{1}$ , $P E_{2}$ & $P E_{3}$ ):

Options:

A .

P E_{1}

>

P E_{2}

>

P E_{3}

B .

P E_{1}

>

P E_{2}

<

P E_{3}

C .

P E_{1}

<

P E_{2}

<

P E_{3}

D .

P E_{1}

<

P E_{2}

>

P E_{3}

Answer: Option B
:
B

Potential Energy $=$ Force $\times$ Displacement $= m g \times h$ where, $m$ is the mass, $g$ is acceleration due to gravity and $h$ is the height.

Since the objects are of the same mass and acceleration due to gravity has a fixed value on earth, the force $m g$ in all three cases are same.

$\Rightarrow$ Potential Energy $= c o n s t a n t \times h$

$\Rightarrow$ Potential energy is directly proportional to its height.

We know that, $h_{1}$ > $h_{2}$ < $h_{3}$ .

Therefore, $P E_{1}$ > $P E_{2}$ < $P E_{3}$

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