Question
If $$\sqrt {\left( {x - 1} \right)\left( {y + 2} \right)} = 7,$$ x and y being positive whole numbers, then the values of x and y respectively are ?
Answer: Option A
$$\eqalign{
& \Leftrightarrow \sqrt {\left( {x - 1} \right)\left( {y + 2} \right)} = 7 \cr
& \Leftrightarrow \left( {x - 1} \right)\left( {y + 2} \right) = {\left( 7 \right)^2} \cr
& \Leftrightarrow \left( {x - 1} \right) = 7{\text{ and}}\left( {y + 2} \right) = 7 \cr
& \Leftrightarrow x = 8{\text{ and }}y = 5 \cr} $$
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$$\eqalign{
& \Leftrightarrow \sqrt {\left( {x - 1} \right)\left( {y + 2} \right)} = 7 \cr
& \Leftrightarrow \left( {x - 1} \right)\left( {y + 2} \right) = {\left( 7 \right)^2} \cr
& \Leftrightarrow \left( {x - 1} \right) = 7{\text{ and}}\left( {y + 2} \right) = 7 \cr
& \Leftrightarrow x = 8{\text{ and }}y = 5 \cr} $$
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