Question
If $$\sqrt {1 + \frac{x}{{169}}} {\text{ = }}\frac{{14}}{{13}}{\text{,}}$$ then x is equal to ?
Answer: Option C
$$\eqalign{
& \Rightarrow \sqrt {1 + \frac{x}{{169}}} = \frac{{14}}{{13}} \cr
& \Rightarrow 1 + \frac{x}{{169}} = \frac{{196}}{{169}} \cr
& \Rightarrow \frac{x}{{169}} = \left( {\frac{{196}}{{169}} - 1} \right) \cr
& \Rightarrow \frac{x}{{169}} = \frac{{27}}{{169}} \cr
& \Rightarrow x = 27 \cr} $$
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$$\eqalign{
& \Rightarrow \sqrt {1 + \frac{x}{{169}}} = \frac{{14}}{{13}} \cr
& \Rightarrow 1 + \frac{x}{{169}} = \frac{{196}}{{169}} \cr
& \Rightarrow \frac{x}{{169}} = \left( {\frac{{196}}{{169}} - 1} \right) \cr
& \Rightarrow \frac{x}{{169}} = \frac{{27}}{{169}} \cr
& \Rightarrow x = 27 \cr} $$
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