Question


How many natural number solutions are there for the equation, A+B+C = 100?


Options:
A .   99C2
B .   99C3          
C .   101C2     
D .   99C99
E .   Cannot be determined
Answer: Option A
:
A

Natural number solutions means each of A,B and C can take a value ≥ 1


This is a Similar to Different question, with a lower limit condition. (Refer ebooklet for indepth explanation)


To take care of the condition, that we are dealing with natural numbers, 


give A,B &C 1 initially


(A+1)+(B+1)+(C+1)=100


Thus, this reduces to A+B+C=97.


This question is now based on arrangement of 97 zeroes and 2 ones=99C2


The answer is 99C2 which is option (a)



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