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Question
How many natural number solutions are there for the equation, A+B+C = 100?
Options:
A .  99C2
B .  99C3          
C .  101C2     
D .  99C99
E .  Cannot be determined
Answer: Option A
:
A
Natural number solutions means each of A,B and C can take a value ≥ 1
This is a Similar to Different question, with a lower limit condition. (Refer ebooklet for indepth explanation)
To take care of the condition, that we are dealing with natural numbers,
give A,B &C 1 initially
(A+1)+(B+1)+(C+1)=100
Thus, this reduces to A+B+C=97.
This question is now based on arrangement of 97 zeroes and 2 ones=99C2
The answer is 99C2 which is option (a)

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