Question


How many different Arithmetic Progressions can you form with atleast three terms with first term 2 and last term 999? 


Options:
A .   1
B .   3
C .   5
D .   6
E .   None of these
Answer: Option A
:
A

Option e


The number of AP’s = (Number of factors of 997 - 1), which is prime.
Hence only one AP’s of 998 terms can be formed.
Answer is option a



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