Question
Given that a real value function g, is such that g(a+b)=a+g(g(b)) & g(0)=0. Find g(102)?
Answer: Option D
:
D
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D
Assumption
Assume a=0, b=0
g(0)=0+g(g(0))=0
Next assume a=1 and b=0
g(1)=1+g(g(0))=1+0=1
continue in the same way, assume a=2, b=0
g(2)=2+g(g(0))=2
Hence g(x)= x itself. Hence g(102)=102
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