Question
From a pack of 52 cards, one card is drawn at random. What is the probability that the card drawn is a ten or a spade?
Options:
A .  $$\frac{4}{13}$$
B .  $$\frac{1}{4}$$
C .  $$\frac{1}{13}$$
D .  $$\frac{1}{26}$$
Answer: Option A
Hence, n (S) = 52
There are 13 spades (including one ten) and there are 3 more ten
Let E = event of getting a ten or a spade
Then, n (E) = (13 + 3) = 16
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{{16}}{{52}} = \frac{4}{{13}}$$

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