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Question

Four persons are chosen at random from a group of 3 men , 2 women and 4 children . The chance that exactly  2 of them are children is :


Options:
A .  `1/9`
B .  `1/5`
C .  `1/12`
D .  `10/21`
Answer: Option D

Let S be the sample space and E be the even of choosing four persons such that  2 of them are children .Then,

    n (S) = number of ways of choosing  4 persons out of 9 .

            = `9_ (C_4) = ((9 xx 8 xx 7 xx 6))/((4 xx 3 xx 2 xx 1))` = 126.

  n(E) = Number of ways of choosing 2 children out of 4 and 2 persons out of (3 + 2) persons .

         = `(4_(C_2) xx 5_(C_2)) =  ((4 xx 3))/((2 xx 1)) xx ((5 xx 4))/(2 xx 1))` = 60.

`:.`      P(E) =  `(n(E))/(n(S)) = 60/126 = 10/21`




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