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Question


Find the number of values of x for which 8x+27x12x+18x=76


Options:
A .   1
B .   2
C .   3
D .   >3
E .   3q+ r
Answer: Option B
:
B
Let 2x=a and  3x=b, the equation becomes
a3+b3a2b+b2a=76
 or a2ab+b2ab=76
 or 6a213ab+6b2=0
(2a3b)(3a2b)=0
Therefore 2x+1=3x+1 or 2x1=3x1 which implies that x= -1 and x= 1. Hence only two solutions exist.

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