Question
Find the number of values of x for which 8x+27x12x+18x=76
Answer: Option B
:
B
Let 2x=a and 3x=b, the equation becomes
a3+b3a2b+b2a=76
or a2−ab+b2ab=76
or 6a2−13ab+6b2=0
(2a−3b)(3a−2b)=0
Therefore 2x+1=3x+1 or 2x−1=3x−1 which implies that x= -1 and x= 1. Hence only two solutions exist.
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:
B
Let 2x=a and 3x=b, the equation becomes
a3+b3a2b+b2a=76
or a2−ab+b2ab=76
or 6a2−13ab+6b2=0
(2a−3b)(3a−2b)=0
Therefore 2x+1=3x+1 or 2x−1=3x−1 which implies that x= -1 and x= 1. Hence only two solutions exist.
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