Question


Find the number of solutions of 13A-18B=2 where A and B are natural numbers between 1 and 100.


Options:
A .   6
B .   5
C .   3
D .   1
E .   7
Answer: Option B
:
B

option (b)


Based on Chinese Remainder theorem


The number can be re-written as 13A=18B+2-------(1)


Reduce the number to 13A=5B+2 (removing 13 from RHS)


Now find the first value of B for which A is an integer. In this case, B=10 is the first value for which A is also an integer.


B=10 and A=14 are the first integer solutions.


A will follow the AP 14 + 18d; d can take values 0 to 4 B will follow the AP 10 + 13d; d can take values 0 to 6A will be the limiting value and hence the solution is 5 and the answer option b)



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