Answer: Option C
If (x - 1) and (x + 1) are the factors y equation then,
$$\eqalign{
& x - 1 = 0 \cr
& x = 1 \cr
& \Rightarrow {\text{Put }}x = 1{\text{, we get }} \cr
& 1 + a - 3 + 2 + b = 0 \cr
& a + b = 0\,.....(i) \cr
& \Rightarrow x + 1 = 0 \cr
& \Rightarrow x = - 1 \cr
& {\text{Put }}x = - 1,{\text{we get }} \cr
& 1 - a - 3 - 2 + b = 0 \cr
& b - a = 4\,.....(ii) \cr
& {\text{After solving (i) & (ii),}} \cr
& {\text{We get }} \cr
& a = - 2,{\text{ }}b = 2 \cr} $$