Question
Find the sum of the following AP 1, 3, 5, 7 …199.
Answer: Option A
:
A
Given,a=1,d=2,an=l=199a+(n−1)d=199
1+(n−1)2=199
⇒1+2n−2=199
⇒2n=200
n=100
Sn=n2(a+l)
Sn=1002(1+199)
Sn=10000
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:
A
Given,a=1,d=2,an=l=199a+(n−1)d=199
1+(n−1)2=199
⇒1+2n−2=199
⇒2n=200
n=100
Sn=n2(a+l)
Sn=1002(1+199)
Sn=10000
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