Question
Construct a parallelogram ABCD in which AB = 4 cm, BC = 5 cm and ∠B=60∘.
Construct a parallelogram ABCD in which AB = 4 cm, BC = 5 cm and ∠B=60∘.
Answer:
:
We know that the opposite sides of a parallelogram are equal.
So, AB = DC = 4 cm
BC = AD = 5 cm
∠B=60∘
∠A+∠B=180∘ [sum of cointerior angles]
∠A=120∘
Steps of Construction
Step I Draw AB = 4 cm.
Step II Draw ray BX such that ∠ABX=60∘.
Step III Mark a point C such that BC = 5 cm.
Step IV Draw a ray AY such that ∠YAB=120∘.
Step V Mark a point D such that AD = 5 cm.
Step VI Join C and D.
Hence, ABCD is required parallelogram.
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:
We know that the opposite sides of a parallelogram are equal.
So, AB = DC = 4 cm
BC = AD = 5 cm
∠B=60∘
∠A+∠B=180∘ [sum of cointerior angles]
∠A=120∘
Steps of Construction
Step I Draw AB = 4 cm.
Step II Draw ray BX such that ∠ABX=60∘.
Step III Mark a point C such that BC = 5 cm.
Step IV Draw a ray AY such that ∠YAB=120∘.
Step V Mark a point D such that AD = 5 cm.
Step VI Join C and D.
Hence, ABCD is required parallelogram.
Was this answer helpful ?
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