Question
Consider the non decreasing sequence of positive integers
1, 2, 2, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 5, 5.... in which nth positive number appears n times. Find theremainder when the 2000th term is divided by 4.
Answer: Option D
:
D
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D
Let us see the sequence of the numbers:
Number Last term of the number
1 1
2 3
3 6
4 10
-- --
N ∑n
We have to find the value of N for the 2000th term. Using iteration we find that if N = 62, the last term that ends with N is (1/2* 62 * 63) = 1953.
Therefore, the next 63 terms are 63. So the 2000th term is 63. So the remainder is 3. Hence option (d)
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