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Aryan runs at a speed of 40m/min. Rahul follows him after an interval of 5min and runs at a speed of 50m/min. Rahul's dog runs at a speed of 60m/min and starts along with Rahul. The dog reaches Aryan and then comes back to Rahul and continues to do so till Rahul reaches Aryan. What is the total distance covered by the dog?
Options:
A .  600m
B .  750m
C .  980m
D .  1200m
Answer: Option D


Let they meet at a distance of Y from start, after time t of Rahul start According to the question 40x(5+t) = 50t 
=> 200+40t = 50t 
=> T= 200/10 = 20min 
=> Y= 50 x t = 50 x 20 = 1000m 
1000m from the options it is evident that all options expect 1200m are smaller than 1000m and dog in any case has to move more than 1000m.



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