Question
An unlimited number of coupons bearing the letters A, B and C are available. What is the possible number of ways of choosing 3 of these coupons so that they cannot be used to spell BAC?
Answer: Option C
:
C
Each of the 3 places can take 3 letters ⇒ 27. But we don't want the combination (A, B, C) ⇒ 3! = 6 are out ⇒ 27-6 = 21. Hence, choice (c) is the right answer.
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:
C
Each of the 3 places can take 3 letters ⇒ 27. But we don't want the combination (A, B, C) ⇒ 3! = 6 are out ⇒ 27-6 = 21. Hence, choice (c) is the right answer.
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