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An iron spherical ball of radius 21cm is melted and it is re-casted in hemispheres of radius 7cm. The number of balls formed will be


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Options:
Answer: Option A
:

The volume will remain constant.


Let's assume x such hemispherical balls will be formed.


So  43πR3=x23πr3
(Where R is the radius of spherical ball and r is the radius of the hemispheres)
43π(21)3=x23π(7)3


x=2×21×21×217×7×7
x=54



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