Question
A plane is flying 2400 km from source A to destination B. Speed of the plane is 600 km/hr and speed of the wind tailing it is 40 km/hr. How many hours after take off would it be faster to go to B than to return to A in case of an emergency
Answer: Option D
:
D
From A to B speed of flight = 640 km/hr , while for the reverse it is = 560 km/hr.
Since, ‘x’ is the distance from A, hence, as per the question:
x560≥(2400−x)640
⇒x≥1120km.
⇒ Minimum such distance = 1120 km and time taken to cover 1120 km =1120560=2hr.
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:
D
From A to B speed of flight = 640 km/hr , while for the reverse it is = 560 km/hr.
Since, ‘x’ is the distance from A, hence, as per the question:
x560≥(2400−x)640
⇒x≥1120km.
⇒ Minimum such distance = 1120 km and time taken to cover 1120 km =1120560=2hr.
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