A paper is in the form of a rectangle ABCD where AB = 22 cm and BC = 14 cm. A semicircle portion with BC as diameter is cut off. Find the area of the remaining paper in cm2.
Options:
A .  221
B .  210
C .  231
D .  240
Answer: Option C : C Area of rectangle = 22×14=308cm2 Area of semicircle = 12×227×(7)2=77cm2 Required area = [Area of rectangle -Area of semicircle] = 308 – 77 = 231cm2
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