Question
A natural number is chosen at random from the first 100 natural numbers. Then the probability, for the in-equation x+100x>50 satisfied, is
Answer: Option B
:
B
x+100x>50⇒x2−50x+100>0⇒1≤x<25−5√21,or25+5√21<x≤100(1≤x≤100,xϵN)
⇒x=1,2,48,49,50,...,100
Therefore the total number of ways = 100 and favorable ways = 55
Required probability =55100=1120.
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:
B
x+100x>50⇒x2−50x+100>0⇒1≤x<25−5√21,or25+5√21<x≤100(1≤x≤100,xϵN)
⇒x=1,2,48,49,50,...,100
Therefore the total number of ways = 100 and favorable ways = 55
Required probability =55100=1120.
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