Question
A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side. What is the ratio of the total surface areas of the smaller cubes and the large cube?
Answer: Option C
- Volume of the large cube = (33 + 43 + 53) = 216 cm3.
Let the edge of the large cube be a.
So, a3 = 216 a = 6 cm.
Required ratio = 6 x (32 + 42 + 52) = 50 = 25 : 18. 6 x 62
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- Volume of the large cube = (33 + 43 + 53) = 216 cm3.
Let the edge of the large cube be a.
So, a3 = 216 a = 6 cm.
Required ratio = 6 x (32 + 42 + 52) = 50 = 25 : 18. 6 x 62
Was this answer helpful ?
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