Question
A large cube is formed from the material obtained by melting three smaller cubes of 3, 4 and 5 cm side . What is the ratio of the total surface areas of the smaller cubes and the large cube ?
Answer: Option C
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Volume of large cube = `(3^3 + 4^3 + 5^3) cm^3 = 216 cm^3`
Let the edge of the large cube be a.
So, `a^3 = 216 rArr a = 6`
`:.` Required ratio = `(6 xx (3^2 + 4^2 + 5^2))/(6 xx 6^2) = 50/36` = 25 : 18
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