Question
A hollow sphere of internal and external diameters 4 cm and 8 cm respectively 18 melted into a cone of base diameter 8 cm. The height of the cone is :
Answer: Option B
Was this answer helpful ?
Volume of material in the sphere = `[ 4/3 pi xx {(4)^3 - (2)^3}] cm^3`
= ` (4/3 pi xx 56) cm^3`
Let the height of the cone be h cm.
Then , `1/3 pi xx 4 xx 4 xx h = (4/3 pi xx 56)`
`hArr h = ((4 xx 56)/(4 xx 4))` = 14 cm.
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution