Question
A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:
Answer: Option B
- External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron = 22 x [(4)2 - (3)2] x 21 cm3 7
= 22 x 7 x 1 x 21 cm3 7
= 462 cm3.
Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg
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- External radius = 4 cm,
Internal radius = 3 cm.
Volume of iron = 22 x [(4)2 - (3)2] x 21 cm3 7
= 22 x 7 x 1 x 21 cm3 7
= 462 cm3.
Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg
Was this answer helpful ?
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