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Question

A hollow iron pipe is 21 cm long and its external diameter is 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm3, then the weight of the pipe is:

Options:
A .  3.6 kg
B .  3.696 kg
C .  36 kg
D .  36.96 kg
E .  None of these
Answer: Option B
 -    External radius = 4 cm,
  Internal radius = 3 cm.
  Volume of iron  =   22   x [(4)2 - (3)2] x 21 cm3 7  
  =   22 x 7 x 1 x 21 cm3 7
  = 462 cm3.
  Weight of iron = (462 x 8) gm = 3696 gm = 3.696 kg

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