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Question

A hemispherical bowl is filled to the brim with a beverage . The contents of the bowl any transferred into a cylindrical

vessel whose radius is 50% more than its height . If the diameter is same for both he bowl and the cylinder, the volume of the beverage in he cylindrical vessel is  :


Options:
A .  `66 22/3`%
B .  `78 1/2`%
C .  100%
D .  More than 100 % (i.e., some liquid will be left in the bowl)
Answer: Option C

Let the height of the vessel be `x` . Then , radius of the bowl = radius of the vessel = `x/2`

Volume of the bowl,     `V_1 = 2/3 pi (x/2)^3   =  1/12  pi x^3`

Volume of the vessel , ` V_2 = pi (x/2)^2 x  =   = 1/4 pi x^3`

Since   `V_2 > V_1` so the vessel can contain  100 % of the beverage filled in he bowl .



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