Question
A dice is rolled twice. What is the probability of getting sum 9?
Answer: Option C
Possible event = 6 × 6 = 36
Favourable outcomes = {(3, 6), {4, 5}, {5, 4}, (6, 3)}
∴ Probability
$$\eqalign{
& = \frac{{{\text{Favourable}}}}{{{\text{total}}}} \cr
& = \frac{4}{{36}} \cr
& = \frac{1}{9} \cr} $$
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Possible event = 6 × 6 = 36
Favourable outcomes = {(3, 6), {4, 5}, {5, 4}, (6, 3)}
∴ Probability
$$\eqalign{
& = \frac{{{\text{Favourable}}}}{{{\text{total}}}} \cr
& = \frac{4}{{36}} \cr
& = \frac{1}{9} \cr} $$
Was this answer helpful ?
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