Question
A cylindrical rod of iron whose height is eight times its radius is melted and cast into spherical balls each of half the radius of the cylinder . The number of spherical balls is :
Answer: Option D
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Let he radius of the cylindrical rod be r.
Then , height of the rod = 8 r and radius of one ball = `r/2`
`:.` Number of balls = `(pi xx r^2 xx 8 r)/(4/3 pi xx (r/2)^3) `
= `((8 xx 8 xx 3)/(4))` = 48
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