Question
A cylindrical tub of radius 12 cm contains water upto a depth of 20 cm. A spherical iron ball is dropped into the tub and thus the level of water is raised by 6.75 cm . The radius of the ball is
Answer: Option D
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Let he radius of the ball be r cm
Volume of ball = Volume of water displaced by it
`:.` `4/3 pi r^3 = pi xx 12 xx 12 xx 6.75`
`rArr r^3 = 9 xx 9 xx 9`
`rArr r = 9 cm`
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