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Question

A cylinder with base  radius of 8 cm and height of 2 cm  is melted to  form a cone of height 6 cm . The radius of the cone will be  :


Options:
A .  4 cm
B .  5 cm
C .  6 cm
D .  8 cm
Answer: Option D

Let the radius of the cone be r cm

Then , `1/3 pi xx r^2 xx 6 = pi xx 8 xx 8 xx 2  `

`hArr    r^2  = ((8 xx 8 xx 2 xx 3)/(6)) = 64`

`hArr  r^2 = 64`

`hArr   r = 8.cm.`




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