Question
A cylinder tube open at boyh ends is made of metal. The internal diameter of the tube is 11.2 cm and its length is 21 cm .The metal everywhere is 0.4 cm thick . Calculate the volume of the metal correct to 1 place of decimal?
Answer: Option B
- Internal diameter = 11.2 cm
Internal radius= 11.2/2 = 5.6 cm Length of the tube = 21 cm
Volume of the internal cylinder π r 2 h = 22x 5.6x5.6x21/7 =2069.76cm 2
External radius, R = (5.6 + 0.4) cm = 6 cm
Volume of the external cylinder = πR2 h =22x6x6x21/7=2376cm2
Now, volume of the metal = Volume of the external diameter – Volume of the internal diameter
= (2376 – 2069.76) cm3 = 306.24 cm3 = 306.2 cm3
Was this answer helpful ?
- Internal diameter = 11.2 cm
Internal radius= 11.2/2 = 5.6 cm Length of the tube = 21 cm
Volume of the internal cylinder π r 2 h = 22x 5.6x5.6x21/7 =2069.76cm 2
External radius, R = (5.6 + 0.4) cm = 6 cm
Volume of the external cylinder = πR2 h =22x6x6x21/7=2376cm2
Now, volume of the metal = Volume of the external diameter – Volume of the internal diameter
= (2376 – 2069.76) cm3 = 306.24 cm3 = 306.2 cm3
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution