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A cord is wound round the circumference of wheel of radius 'r'. The axis of the wheel is horizontal and moment of inertia about it is 'I'. A weight 'mg' is attached to the end of the cord and falls from rest. After falling through a distance h, the angular velocity of the wheel will be
Options:
A .  √2ghI+mr
B .  √2mghI+mr2
C .  √2mghI+2mr2
D .  √2gh
Answer: Option B
:
B
According to law of conservation of energy mgh=12(I+mr2)ω2ω=2mghI+mr2.

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