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Question

A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:

Options:
A .  49 sq mt
B .  50 sq mt
C .  53.5 sq mt
D .  55 sq mt
E .  None of these
Answer: Option A
 -     Area of the wet surface = [2(lb + bh + lh) - lb]
  = 2(bh + lh) + lb
  = [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2
  = 49 m2.

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