Question
A cistern 6 m long and 4 m wide contains water up to a depth of 1 m 12 cm . The total area of the wet surface is :
Answer: Option A
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Area of the wet surface = [ 2 ( lb + bh + lh) - lb] = 2( bh + lh) + lb
= [2 ( 4 x 1.25 + 6 x 1.25) + 6 x 4] `m^2`
= 49 `m^2`
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