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Question
A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is-
Options:
A .  $$\frac{1}{13}$$
B .  $$\frac{2}{13}$$
C .  $$\frac{1}{26}$$
D .  $$\frac{1}{52}$$
Answer: Option C
Hence, n(S) = 52
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2
$$\therefore P(E) = \frac{{n(E)}}{{n(S)}} = \frac{2}{{52}} = \frac{1}{{26}}$$

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