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Question
A box contains nine bulbs out of which 4 are defective. If four bulbs are chosen at random, find the probability that exactly three bulbs are good.
Options:
A .  20/31
B .  20/63
C .  5/31
D .  6/31
E .  26/31
Answer: Option B


Required probability = (⁵C₃ . ⁴C₁)/⁹C₄ = (10 * 4)/126 = 20/63



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