Question
A bag contains 6 white and 4 red balls . three balls are drawn at random . What is the probability that one ball is red and he other two are white ?.
Answer: Option A
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Let S be the sample space . Then ,
n(S) = number of ways of drawing 3 balls out of 10
= `10_(C_3) = ((10 xx 9 xx 8))/((3 xx 2 xx 1))` = 120.
Let E = event of drawing 1 red and 2 white balls
`:.` n(E) = Number of ways of drawing 1 red ball out of 4 and 2 white ball out of 6 .
= `(4_(C_1) xx 6_ (C_2)) = (4 xx (6 xx 5)/(2 xx 1))` = 60.
`:.` P (E) = ` (n(E))/(n(S)) = 60/120 = 1/2`
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