Question
A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
Answer: Option B
$$\eqalign{
& {\text{Let}}\,{\text{number}}\,{\text{of}}\,{\text{balls}} \cr
& = \left( {6 + 8} \right) \cr
& = 14 \cr
& {\text{Number}}\,{\text{of}}\,{\text{white}}\,{\text{balls}} = 8 \cr
& P\left( {{\text{drawing}}\,{\text{a}}\,{\text{white ball}}} \right) \cr
& = \frac{8}{{14}} = \frac{4}{7} \cr} $$
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$$\eqalign{
& {\text{Let}}\,{\text{number}}\,{\text{of}}\,{\text{balls}} \cr
& = \left( {6 + 8} \right) \cr
& = 14 \cr
& {\text{Number}}\,{\text{of}}\,{\text{white}}\,{\text{balls}} = 8 \cr
& P\left( {{\text{drawing}}\,{\text{a}}\,{\text{white ball}}} \right) \cr
& = \frac{8}{{14}} = \frac{4}{7} \cr} $$
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