Question
A walks at a uniform rate of 4km an hour and 4 hours after his start, B cycles after his at the uniform rate of 10km an hour. How far from than starting point will B catch A?
Answer: Option D
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Suppose B catches A after x hours then,
Distance between travel by A in (x+4)hours = Distance travelled by B in x hours
=> 4(x+4) =10x
=> 6x = 16
=> 3x = 8
=> X = 8/3 hrs
Distance travelled by B in 8/3 hrs
=(8/3 x 10)km = 80/3 km = 26.7 km
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