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Question
A walks at a uniform rate of 4km an hour and 4 hours after his start, B cycles after his at the uniform rate of 10km an hour. How far from than starting point will B catch A?
Options:
A .  16.7km
B .  18.6km
C .  21.5km
D .  26.7km
Answer: Option D


Suppose B catches A after x hours then, 
Distance between travel by A in (x+4)hours = Distance travelled by B in x hours 
=> 4(x+4) =10x 
=> 6x = 16 
=> 3x = 8 
=> X = 8/3 hrs 
Distance travelled by B in 8/3 hrs 
=(8/3 x 10)km = 80/3 km = 26.7 km



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