Question
A train running at $7/11$ of its own speed reached a place in 22 hours. How much time could be saved if the train would run at its own speed?
Answer: Option B
Answer: (b)Since the train runs at $7/11$ of its own speed,the time it takes is $11/7$ of its usual speed.Let the usual time taken be t hours.Then we can write, $11/7$ t = 22t = ${22 × 7}/11$ = 14 hoursHence, time saved= 22 - 14 = 8 hours
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Answer: (b)Since the train runs at $7/11$ of its own speed,the time it takes is $11/7$ of its usual speed.Let the usual time taken be t hours.Then we can write, $11/7$ t = 22t = ${22 × 7}/11$ = 14 hoursHence, time saved= 22 - 14 = 8 hours
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