Question
A train running at `7/11` of its own speed reached a place in 22 hours. How much time could be saved if the train would have run at its own speed ?
Answer: Option B
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New speed = `7/11` of usual speed.
`:.` New time = `11/7` of usual time.
So `11/7` of usual time = 22 hrs. `rArr `usual time =`((22 xx 7)/(22))` = 14 hrs.
Hence , time saved = (22 - 14) = 8 hrs.
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