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Question

A thief steals a car at 2.30 p.m. and drives it at 60 kmph. The theft is discovered at 3 p.m. and the owner sets off in another car at 75 kmph. When will he overtake he thief ?


Options:
A .  4.30 p.m.
B .  4.45 p.m.
C .  5 p.m.
D .  5.15 p.m.
Answer: Option C

Suppose he thief is overtaken  `x` hrs after 2.30 p.m.

Then , distance covered by he thief in `x` hrs.    = distance covered by the owner in `(x - 1/2)` hrs.

`:.`       `60x = 75(x - 1/2)`

`hArr     15x =  75/2       hArr   x = 5/2` hrs.

So, the thief is overtaken at 5 p.m.



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